Answer:
C4H8
Explanation:
First find the molar mass of CH2;
2(1.01) + 1(12.01) = 14.03g
Now divide the molar mass of the compound by the molar mass of CH2;
56g/14.03g = 3.9914 Round to nearest whole number = 4
Multiply CH2 by 4 to get the molecular formula;
CH2* 4 = C4H8
Answer:
The acceleration of the object equals the gravitational acceleration. The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration
Animals contribute water mainly through breathing, perspiration and urination. ... When droplets of sweat evaporate from the surface of an animal's skin, they take a bit of the animal's body heat with them. They also turn into water vapor and enter the water cycle, just like water evaporating from plant leaves.
Molar mass of NH_3



We know.
No of moles=Given mass/Molar mass


Now
Lets write the balanced equation

- There is 2moles of Ammonia
- 3moles of H_2
- 1mole of N_2
Now

For Hydrogen



For Ammonia



For Nitrogen

