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exis [7]
2 years ago
8

HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED

Chemistry
1 answer:
kramer2 years ago
5 0

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

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When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e
sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂  

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

                2 Al(s)  +  3Cl₂(g)  ⇒   2AlCl₃

Process

a) Calculate the molar mass of the reactants  

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion  Al/Cl₂ = 53.96/212.7 = 0.254

   Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

                    53.96 g of Al ------------------ 212.7 g of Cl₂

                     40.5 g of Al -------------------  x

                      x = (40.5 x 212.7) / 53.96

                      x = 8614.35 / 53.96

                      x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

                  = 53.057 g

d) Calculate the moles of Cl

                       35.45 g of Cl ----------------- 1 mol

                       53.057 g of Cl ---------------  x

                        x = (53.057 x 1)/35.45

                       x = 1.49 mol of Cl₂                    

6 0
3 years ago
Read 2 more answers
2 Points
inessss [21]

Answer: D is the correct answer

Explanation: When there is no insulator surrounding a metal wire then there is nothing to stop the electrons from flowing outside of the wire, This means that anything the wire comes in contact with could get shocked or burnt when there is a current flowing through the wire.

7 0
3 years ago
Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40 minutes t
Inessa [10]

2 m/s

Explanation:

The distance to school is 14.4 kilometers which are equal to 14400 meters.

Amy takes 40 minutes which are equal to 40 × 60 = 2400 seconds to arrive at school.

Bill takes 40 + 20 = 60 minutes which are equal to 60 × 60 = 3600 seconds to arrive at school.

Amy’s average speed = distance (m) / time (s)

Amy’s average speed = 14400 m / 2400 s = 6 m/s

Bill’s average speed = 14400 m / 3600 s = 4 m/s

How much faster (in meters/second) is Amy’s average speed for the entire trip?

Amy’s average speed - Bill’s average speed = 6 m/s - 4 m/s = 2 m/s

Learn more about:

average speed

brainly.com/question/10436437

#learnwithBrainly

3 0
3 years ago
Copper is a solid phase of copper still unknown to science. The only difference between it and ordinary copper is that Copper fo
Scrat [10]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The density is  \rho =  8.21479 g/cm^3

Explanation:

From the question we are told that

         the lattice constant is  a =  0.295 nm = 0.295*10^{-9} = 0.295*10^{-7} cm

The density of Copper (\beta) is mathematically represented as

     \rho  =  \frac{ZM}{a^3N_A}

Where  Z is the number of units in a unit cell and  for BCC crystals  Z =2

          M is the molar mass of copper which same for Copper with a value of  

           M =  63.5  g/mol

          N_A is the Avogadro's constant with a value of  N_A =  6.022*10^{23}

Substituting values

       \rho =  \frac{2 *63.5}{(0.295*10^{-7})^3 * (6.022*10^{23})}

      \rho =  8.21479 g/cm^3

       

8 0
2 years ago
What type of bond has a repeating pattern of positive and negative ions?
grigory [225]
Ionic bond I think. It is the only one related to ions.
8 0
3 years ago
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