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4 years ago

Why a increase in volume causes a decrease in pressure

Chemistry

1 answer:

Sergio [31]4 years ago

8 0

Answer:

If pressure increases, then volume decreases and vice versa, when temperature is held constant.” When pressure increases, the same number of molecules, or matter, are being forced closer together to occupy a shrinking space, their volume decreasing while their density correspondingly increases.

Explanation:

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Using d = m/V, what is the (V)olume of a solid that has a density is 14g/cm² and has a

Simora [160]

Answer:

0.5cm²

Explanation:

the volume is found by dividing the mass over the density

v=m/d

=7g/14g/cm²

=0.5cm²

i hope this helps

3 0

3 years ago

Read 2 more answers

The density of solid Ag is 10.5 g/cm3. How many atoms are present per cubic centimeter of Ag?

Sveta_85 [38]

Answer:

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

Edge length = $4.1\times 10^{-8}\ cm$

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = $\frac{10.5\ g/cm^3}{107.8682\ g/mol}$ =0.0973 mol/cm³

Also, 1 mole = $6.023\times 10^{23}$ atoms.

So,

Atoms present per cm³ of Ag = $0.0973\ mol/cm^3\times 6.023\times 10^{23}\ atoms/mol=5.8\times 10^{22}\ atoms/cm^3$

Thus, answer = $5.8\times 10^{22}\ atoms/cm^3$

In FCC, the number of atoms in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag = $\frac{5.8\times 10^{22}\ atoms/cm^3}{4}=1.45\times 10^{22}\ unit\ cells /cm^3$

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So, $Volume=\frac{1}{1.45\times 10^{22}\ unit\ cells /cm^3}=68.9\times 10^{-24}\ cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

(c)

Also, Volume = ${(Edge\ length)}^3$

Thus, edge length = ${Volume}^{\frac{1}{3}}$ = $\left(68.9\times \:\:10^{-24}\right)^{\frac{1}{3}}\ cm=4.1\times 10^{-8}\ cm$

Edge length = $4.1\times 10^{-8}\ cm$

5 0

4 years ago

Based on periodic properties, identify a molecule, X2, that is likely to react with Sr in a way similar to how Cl2 reacts with S

iris [78.8K]

Answer:

F2, Br2, I2

Explanation:

The halogen diatomic molecules have a general formula X2. Based on periodic properties, the halogens all have similar chemical behavior. This implies that, F2, Cl2, Br2 and I2 all have similar chemical properties.

All these other X2 halogen molecules are likely to react with St, just as Cl2 does.

5 0

3 years ago

Which of the following elements has the smallest atomic radius?

HACTEHA [7]

Fluorine has the smallest atomic radius at a 42

3 0

4 years ago

Read 2 more answers

A reaction has a ΔHrxn=54.2 kJ. Calculate the change in entropy for the surroundings (ΔSsurr) for the reaction at 25.0 °C. (Assu

Marysya12 [62]

Answer:

b. - 184 J/K

Explanation:

ΔSsurr = - ΔH/T....at constant P and T.

∴ ΔHrxn = 54.2 KJ = 54200 J

∴ T = 25°C ≅ 298.15 K

⇒ ΔSsurr = - (54200 J)/(298 K)

⇒ ΔSsurr = - 182 J/K ≅ - 184 J/K

6 0

3 years ago