Answer:
3.08 moles of CaF₂ and 3.08 mol of H₂SO₄
Explanation:
In order to produce HF we can assume this chemical reaction:
CaF₂ + H₂SO₄ → CaSO₄ + 2HF
1 mol of calcium fluoride can react to 1 mol of sulfuric acid in order to produce 1 mol of calcium sulfate and 2 moles of HF
In this case, ratio is 2:1 with both reactants. Let's make a rule of three:
2 moles of HF were produced by 1 mol of CaF₂ and 1 mol of H₂SO₄
Then, 6.16 moles of HF must be produced by:
(6.16 . 1) / 2 = 3.08 moles of CaF₂ and 3.08 mol of H₂SO₄
<u>Answer:</u>
The freezing point of a 1.7 mole aqueous ethylene glycol solution is 3.2°C
<u>Explanation:</u>
Moles present in aqueous ethylene glycol solution= m=1.7
Depression constant for water = = 1.8 deg C/m
According to formula
=1.8* 1.7
=3.2
Hence the freezing point of aqueous ethylene glycol solution is 3.2°C
Gas particles want to be as free as they can, occupying as much space as they can because they are independent and the greater the temperature the greater their speed, when the temperature is low so is their speed, so they can attach to solvent molecules. When the temperature rises the gas molecules become more agitated and the glue can no longer take them inside the solvent.
Hope this helps!