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Greeley [361]
3 years ago
11

A reaction has a ΔHrxn=54.2 kJ. Calculate the change in entropy for the surroundings (ΔSsurr) for the reaction at 25.0 °C. (Assu

me constant pressure and temperature.)a. -0.184 J/K
b. -184 J/K
c. 1.66 J/K
d. 184 J/K
Chemistry
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

b. - 184 J/K

Explanation:

  • ΔSsurr = - ΔH/T....at constant P and T.

∴ ΔHrxn = 54.2 KJ = 54200 J

∴ T = 25°C ≅ 298.15 K

⇒ ΔSsurr = - (54200 J)/(298 K)

⇒ ΔSsurr = - 182 J/K ≅ - 184 J/K

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Explanation :

In organic chemistry, a carbonyl group is a functional group which contain a carbon atom double-bonded to an oxygen atom i.e, ( C=O).

     If carbonyl group is present in a compound then it can be a carboxylic (RCOOH), aldehyde (RCHO), ketone (RCOR'), ester ((RCOOR') or amide (RCONR'R") group.

Here are some functional groups naming according to the<em> IUPAC</em> rules and image also attached,

Carboxylic acid   →    (RCOOH)    →    ( name end in 'OIC ACID' )

Aldehyde             →    (RCOH)       →    ( name end in 'AL' )

Ketone                 →    (RCOR')       →    ( name end in 'ONE' )

Ester                     →    (RCOOR')    →    ( name end in 'ATE' )

Amide                   →    (RCONR'R") →    ( name end in 'AMIDE' )

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