<h3>Changes with the independent variable...</h3>
Answer:
Name Formula and Charge Name Formula and Charge
ammonium NH4+ hydroxide OH−
acetate C2H3O2−, or CH3COO− nitrate NO3−
bicarbonate (hydrogen carbonate) HCO3− nitrite NO2−
bisulfate (hydrogen sulfate) HSO4− peroxide O22−
carbonate CO32− perchlorate ClO4−
chlorate ClO3− phosphate PO43−
chromate CrO42− sulfate SO42−
cyanide CN− sulfite SO32−
dichromate Cr2O72− triiodide I3−
Explanation:
Answer:
The answer to your question is the second option: 2M NaOH solution
Explanation:
Data
Volume 1 = 0.5 l
Concentration 1 = 12 M NaOH
Volume 2 = 3 l
Concentration 2 = ?
Formula
V₁C₁ = V₂C₂
Solve for C₂
C₂ = V₁C₁ / V₂
Substitution
C₂ = (0.5)(12) / 3
Simplification and result
C₂ = 6 / 3
C₂ = 2 M
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