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3 years ago

When weak acids react with strong bases, the H+ from the weak acid is transferred to the:

Chemistry

2 answers:

Ber [7]3 years ago

7 0

To the OH- from the ztrong base to form water and salt

Aloiza [94]3 years ago

7 0

Answer:

The correct option is OH⁻ from the strong base to form water and a salt

Explanation:

The reaction between an acid and a base is called a neutralization reaction. A neutralization reaction is the reaction between an acid (weak or strong) and a base (weak or strong) to produce salt and water. Here, the hydrogen ion (H⁺) ionized from the acid combines with the hydroxyl ion (OH⁻) ionized from the base to produce water. While the metallic cation from the base combines with the nonmetallic anion from the acid to form salt.

The illustration provided in the question is no different, although a weak acid ionizes partially in water i.e not all the hydrogen atoms are ionized to form hydrogen ions.

Examples of such reactions between a weak acid

(CH₃COOH) and a strong base (NaOH) is

CH₃COOH + NaOH ⇒ CH₃COONa + H₂O

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An analytical chemist is titrating 181.2 mL of a 0.09000M solution of diethylamine ((CH) NH) with a 0.5400M solution of HNO3. Th

gavmur [86]

Answer:

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Explanation:

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2 years ago

Where do you place the symbols that represent the state of matter in an equation?

nexus9112 [7]

Subscript in a pair of brackets

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3 years ago

A sample of sodium sulfite has a mass of 2.80 g.

Gnom [1K]

<u>Answer:</u>

<u>For a:</u> The number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

<u>For b:</u> The number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

<u>For c:</u> The mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

<u>Explanation:</u>

The chemical formula of sodium sulfite is $Na_2SO_3$ . It is formed by the combination of 2 sodium $(Na^+)$ ions and 1 sulfite $(SO_3^{2-})$ ions

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium sulfite = 2.80 g

Molar mass of sodium sulfite = 126 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium sulfite}=\frac{2.80g}{126g/mol}=0.022mol$

<u>For a:</u>

Moles of sodium ions in sodium sulfite = (2 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(2\times 0.022\times 6.022\times 10^{23})=2.65\times 10^{22}$ number of sodium ions

Hence, the number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

<u>For b:</u>

Moles of sulfite ions in sodium sulfite = (1 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(1\times 0.022\times 6.022\times 10^{23})=1.325\times 10^{22}$ number of sulfite ions

Hence, the number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

<u>For c:</u>

Molar mass of sodium sulfite = 126 g/mol

According to mole concept:

$6.022\times 10^{23}$ number of formula units are present in 1 mole of a compound

Or, $6.022\times 10^{23}$ number of formula units of sodium sulfite have a mass of 126 grams

So, 1 formula unit of sodium sulfite will have a mass of = $\frac{126}{6.022\times 10^{23}}\times 1=2.09\times 10^{-22}g$

Hence, the mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

7 0

3 years ago

Fe2O3 + 2Al = 2Fe + Al2O3 is this a redox reaction

katovenus [111]

Answer:

<h3>2Al+ Fe2O3 gives 2Fe + Al2O3. The given reaction is a redox reaction. As oxidation and reduction are taking place simultaneously.</h3>

Explanation:

like this...Identify oxidation and reduction with their agents:

<h3>•Fe2O3 is reduced to Fe whereas Al is oxidized to Al2O3</h3>

<h3>In the above reaction:</h3>

<h3>Oxidizing agent:Fe2O3</h3>

<h3>Reducing agent:Al</h3>

I hope it's help you (◠‿・)—☆

5 0

2 years ago

The standard free energy of formation, ΔG∘f, of a substance is the free energy change for the formation of one mole of the subst

OLEGan [10]

Answer:

B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG∘f=−451.0 kJ/mol

D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol

Explanation:

The spontaneity of a reaction is given by the value of the standard Gibbs free energy of the reaction (ΔG°rxn). The more negative is the ΔG°rxn, the more spontaneous is a reaction.

The ΔG°rxn can be calculated using the following expression:

ΔG°rxn = ∑np × ΔG°f(products) − ∑nr × ΔG°f(reactants)

By definition, the standard Gibbs free energy of formation of simple substances in their most stable state is zero. That is why, in the reaction of formation of a compound ΔG°rxn = ΔG°f(product).

<em>Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? </em>

<em> </em>Not feasible. ΔG°rxn = ΔG°f(product) > 0.

Feasible. ΔG°rxn = ΔG°f(product) < 0.

Not feasible. ΔG°rxn = ΔG°f(product) > 0.

Feasible. ΔG°rxn = ΔG°f(product) < 0.

3 0

3 years ago