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3 years ago

When weak acids react with strong bases, the H+ from the weak acid is transferred to the:

Chemistry

2 answers:

Ber [7]3 years ago

7 0

To the OH- from the ztrong base to form water and salt

Aloiza [94]3 years ago

7 0

Answer:

The correct option is OH⁻ from the strong base to form water and a salt

Explanation:

The reaction between an acid and a base is called a neutralization reaction. A neutralization reaction is the reaction between an acid (weak or strong) and a base (weak or strong) to produce salt and water. Here, the hydrogen ion (H⁺) ionized from the acid combines with the hydroxyl ion (OH⁻) ionized from the base to produce water. While the metallic cation from the base combines with the nonmetallic anion from the acid to form salt.

The illustration provided in the question is no different, although a weak acid ionizes partially in water i.e not all the hydrogen atoms are ionized to form hydrogen ions.

Examples of such reactions between a weak acid

(CH₃COOH) and a strong base (NaOH) is

CH₃COOH + NaOH ⇒ CH₃COONa + H₂O

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Answer:

The cohesive nature of the molecules

Explanation:

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3 years ago

Mention the significance of dams and irrigation canals?

GarryVolchara [31]

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2 years ago

What types of elements are useful for dating materials?

zalisa [80]

c. the answer is radioactive elements are useful for dating materials

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3 years ago

Read 2 more answers

Be sure to answer all parts. A 0.365−mol sample of HX is dissolved in enough H2O to form 835.0 mL of solution. If the pH of the

Marta_Voda [28]

Answer:

The Ka is 9.11 *10^-8

Explanation:

Step 1: Data given

Moles of HX = 0.365

Volume of the solution = 835.0 mL = 0.835 L

pH of the solution = 3.70

Step 2: Calculate molarity of HX

Molarity HX = moles HX / volume solution

Molarity HX = 0.365 mol / 0.835 L

Molarity HX = 0.437 M

Step 3: ICE-chart

[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4

Initial concentration of HX = 0.437 M

Initial concentration of X- and H3O+ = 0M

Since the mole ratio is 1:1; there will react x M

The concentration at the equilibrium is:

[HX] = (0.437 - x)M

[X-] = x M

[H3O+] = 1.995*10^-4 M

Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4

[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M

[X-] = x = 1.995*10^-4 M

Step 4: Calculate Ka

Ka = [X-]*[H3O+] / [HX]

Ka = ((1.995*10^-4)²)/ 0.437

Ka = 9.11 *10^-8

The Ka is 9.11 *10^-8

4 0

3 years ago

15° 25 2p 35"

nataly862011 [7]

B. Lower elements have more energy levels

Explanation:

Ionization energy decreases down the group because lower elements have more energy levels. Therefore, the pull of the nucleus on the outermost shell electrons is not so great.

Ionization energy is the energy required to remove an electron from an atom.
It is a measure of the readiness of an atom to lose an electron.
Down a group or family, atomic radius increases due to addition of more electronic shells or energy levels.
As the atomic radius becomes larger, the ionization energy reduces.
This is because of the increased shielding/screening effect of inner shell electrons on the electron to be removed from the nuclear attraction.
This way, its takes a lesser amount of energy to remove them as shielding effects increases down the group.

Learn more:

ionization energy brainly.com/question/1971327

#learnwithBrainly

6 0

3 years ago