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Morgarella [4.7K]
3 years ago
8

List three different ways to write 5^11 as the product of two powers. Explain why all three of your expressions are equal to 5^1

1
Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0
In multiplying quantities of the same base, the product is simply the base raised to a power that is the sum of the individual powers of the factors. That is, (a^n)(a^m)= a^{n+m}

The term 5^{11} can be expressed as the product of two factors with the same base (which is five) and whose powers add up to 11. Three examples are:
(5^1)(5^{10}) = 5^{1+10} = 5^{11} \\ (5^5)(5^6) = 5^{5+6} = 5^{11} \\ 
(5^8)(5^3) = 5^{8+3} = 5^{11}
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Kobotan [32]

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3 years ago
Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

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3 years ago
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tino4ka555 [31]

Answer:

x = 24

Step-by-step explanation:

10:8

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7 0
3 years ago
Read 2 more answers
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11Alexandr11 [23.1K]

Answer: 15

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3 years ago
In the game of Pick-A-Ball, there are 10 colored balls: 2 red, 4 white, and 4 blue. The balls have been placed into a small buck
MaRussiya [10]

Answer:

The probability of selecting the color of ball that you just selected(a red ball) is P(r) =  \frac{2}{10}

Step-by-step explanation:

From the question we are told that

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   The number of red balls is r =  2 red

    The number of white ball is  w =  4

    The number of blue balls is  b  =  4

   The number of balls to be selected is  N  =  2 balls

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Here P(A) is the probability of obtaining the exact sequence of result  and from the question it  is  P(A) =  0.10

Generally my price according to the question is  

     k =  \frac{0.10 }{10}

=>   k =  0.01

Let assume we selected a red ball

 Generally the probability of selecting a red ball is  mathematically represented as

       P(r) =  \frac{2}{10}

8 0
3 years ago
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