Answer:
I would think the correct answer would be B and D.
Explanation:
The information the institutions gathered doesn't tell whether the temperature increased or decreased so it couldn't be A. And the data that is gathered by each institute is similar to one another, so it couldn't be C. Therefore, you're left with B and D.
I hope this helps!
The sum of the oxidation numbers of all atoms in a neutral compound is zero.
Answer:
25.3 g of KNO₃ contain 0.25 moles.
Explanation:
Given data:
Number of moles of KNO₃ = ?
Mass of KNO₃ = 25.3 g
Solution:
Formula:
Number of moles = mass/ molar mass
Molar mass of KNO₃:
KNO₃ = 39 + 14+ 16×3
KNO₃ = 101 g/mol
Now we will put the values in formula.
Number of moles = 25.3 g/ 101 g/mol
Number of moles = 0.25 mol
Thus, 25.3 g of KNO₃ contain 0.25 moles.
Answer:
32.6%
Explanation:
Equation of reaction
2KClO₃ (s) → 2KCl (s) + 3O₂ (g)
Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)
Molar volume of Oxygen at s.t.p = 22.4L / mol
since the gas was collected over water,
total pressure = pressure of water vapor + pressure of oxygen gas
0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C
pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1
P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p
Using ideal gas equation
= 
V2 = 
V2 = 664.1052 ml
245.2 yielded 67.2 molar volume of oxygen
0.66411 will yield = 
= 2.4232 g
percentage of potassium chlorate in the original mixture = 
= 32.6%
Explanation:
First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.
