Which is the correct choice

Chemistry

1 answer:

umka21 [38]3 years ago

4 0

Answer:2 Fr because is has the lowest electronegativity 0.79

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What systems are working during the process of respiration?

Natali5045456 [20]

respiratory and lymphatic

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3 years ago

4Na + O2 2Na2O

beks73 [17]

4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98

g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
2

m
o
l
×
61.98

g
⋅
m
o
l
−
1

=

154.95

g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go

5 0

3 years ago

The higher up you go, it gets harder to breathe because air is less dense which means that there are ____________ molecules of o

Papessa [141]

Less is the word to ur question

7 0

3 years ago

Read 2 more answers

A mixture contains only nacl and al2(so4)3. a 1.45 g sample of the mixture is dissolved in water, and an excess of naoh is added

Aleks [24]

When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced. The balanced chemical reaction is represented as-

Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄

On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.

As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.

So, mass percentage of Al₂(SO₄)₃ is= (amount of Al₂(SO₄)₃/total amount of mixture)X100 = $\frac{1.085 X 100}{1.45}$ =74.8 %.

7 0

3 years ago

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Feliz [49]

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of $H_{2}O_{2}$ is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

$Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g$

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

3 0

3 years ago