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lakkis [162]
3 years ago
9

Lead(II) sulfide, PbS, reacts with oxygen gas to produce lead(II)oxide and dioxide. If 0.500 moles of O2 were consumed using thi

s chemical reaction, how much of lead(II)would be produced?
Chemistry
1 answer:
Brrunno [24]3 years ago
3 0
The balanced chemical reaction is written as:

PbS<span> + 3/2</span>O2<span> = PbO + SO2

We  are given the amount of oxygen to be consumed in the reaction. We use this amount for the calculations. We do as follows:

0.500 mol O2 ( 1 mol PbO / 3/2 mol O2) = 0.33 mol PbO is to be produced</span>
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