The resolution of a camera or other optical system is determined by the relationship between that two scales of Light waves of different wavelengths produce diverse colors.
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
The distance between the crests or troughs of a wave motion is referred to as the wavelength () of light. 2. Frequency (f) - The frequency of a repeated event is the number of instances per unit of time. Frequency in the context of light is the number of wavelength repetitions per second.
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Answer:
541.14 m/s
Explanation:
We are given that
Mass of cannon=
Mass of shell,
Initial velocity of shell,v=547 m/s
We have to find the velocity of shell fired from this loose cannon.
According to law of conservation of momentum
Initial momentum of system=0
When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell
Kinetic energy of shell,
K.E of shell=
K.E of shell=
K.E of shell=
2K.E of shell=
Velocity of shell fired from this loose cannon,v_2=
Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s
Answer:
Explanation:
h = height of the cliff
Consider upward direction as positive and downward direction as negative
Consider the motion of rock thrown straight up :
Y = vertical displacement = - h
v₀ = initial velocity = 8.63 m/s
a = acceleration = - 9.8 m/s²
t = time taken to hit the ground = 3 s
Using the equation
Y = v₀ t + (0.5) a t²
- h = (8.63) (3) + (0.5) (- 9.8) (3)²
h = 18.21 m
Consider the motion of rock thrown down :
Y' = vertical displacement = - 18.21
v'₀ = initial velocity = - 8.63 m/s
a' = acceleration = - 9.8 m/s²
t' = time taken to hit the ground = ?
Using the equation
Y' = v'₀ t' + (0.5) a' t'²
- 18.21 = (- 8.63) t' + (0.5) (- 9.8) t'²
t' = 1.2 s
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
Answer:
nope dont agree with that i think it would b a lot harder to do on a mass scale like that
Explanation:
Only way to do that is if aliens with far superior technology wise came to earth and did it
