Answer:
2.9 m/s
Explanation:
Momentum will be conserved
Speed of the ball just before collision is
v = √2gh = √(2(9.8)(0.8)) = 3.96 m/s
The initial momentum is 1.3(3.96) = 5.15 kg•m/s
The block takes away momentum of 0.6(2.2) = 1.32 kg•m/s
Leaving the ball with momentum of 5.15 - 1.32 = 3.83 kg•m/s
vf(ball) = 3.83 / 1.3 = 2.946... ≈ 2.9 m/s
Answer:
4N
Explanation:
a = (7-3)/5 = 0.8m/s^2
F = ma = (5)(0.8) = 4 Newtons
The second option rolling friction
It is the third option, buoyant force.
Answer:
Graph B represents correct graph for velocity time
Explanation:
Initially the object is dropped under the influence of constant force due to gravity
So here we can say its acceleration is constant due to gravity
hence here the velocity will increase downwards due to gravity and it is given as

now when it enters into the pool an upward force of same magnitude will act on it
so net force on it is

so here we will have no acceleration and it will move with constant speed after that
so here correct graph is
Graph B