Answer:
C 0.85 j/g*k
Explanation:
The specific heat capacity of a material is given by:
where
Q is the amount of heat supplied to the object
m is the mass of the object
is the increase in temperature of the object
For the object in this problem, we have
m = 117 g is the mass
Q = 1200 J is the heat supplied
is the increase in temperature
Substituting into the formula, we find the specific heat:
Answer:
I don't understand what exactly you're asking, but this statement is true.
Explanation:
A - 3
B - 1
C - 2
D - 4
E - 5
Answer:
Very easy question
For x-component, we use Fₓ = Fcosα
For y-component, we use Fy = Fsinα
The major problem is with angle α.
Here α = 90+30
Because the angle is measured from +ve X-axis.
By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.
So for further calculation,
Fₓ = Fcos(90+30) = 25(-sin30)
Fₓ = -25(1/2) = 25/2 = 12.5 - will be eliminate because force in magnitude is not "-ve"
As it is
Fy = Fsin(90+30) = Fcos30
Fy = 25 (√3 /2) = 25√3/2
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