Silver is a very good conductor, this means its resistivity is very low (from table, we can check the precise value, which is
![\rho_s = 1.6 \cdot 10^{-8} \Omega m](https://tex.z-dn.net/?f=%5Crho_s%20%3D%201.6%20%5Ccdot%2010%5E%7B-8%7D%20%5COmega%20m)
).
Pure water, instead, is a very bad conductor, this means its resistivity is very high, of order of
![k \Omega \cdot m](https://tex.z-dn.net/?f=k%20%5COmega%20%5Ccdot%20m)
(
![10^3 \Omega m](https://tex.z-dn.net/?f=10%5E3%20%5COmega%20m)
). Even without knowing the precise value of the pure water resistivity, we can estimate the ratio between the pure water resistivity and the silver resistivity by comparing the two orders of magnitude:
![r= \frac{10^3 \Omega m}{10^{-8} \Omega m} \sim 10^{11}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B10%5E3%20%5COmega%20m%7D%7B10%5E%7B-8%7D%20%5COmega%20m%7D%20%20%5Csim%2010%5E%7B11%7D%20)
Therefore, we can say that the correct answer is
Answer:
Lifting force, F = 21240 N
Explanation:
It is given that,
Mass of the helicopter, m = 1800 kg
It rises with an upward acceleration of 2 m/s². We need to find the lifting force supplied by its rotating blades. It is given by :
F = mg + ma
Where
mg is its weight
and "ma" is an additional acceleration when it is moving upwards.
So, ![F=1800\ kg(9.8\ m/s^2+2\ m/s^2)](https://tex.z-dn.net/?f=F%3D1800%5C%20kg%289.8%5C%20m%2Fs%5E2%2B2%5C%20m%2Fs%5E2%29)
F = 21240 N
So, the lifting force supplied by its rotating blades is 21240 N. Hence, this is the required solution.
Answer:
1. The precession of the equinoxes.
2. Changes in the tilt angle of Earth’s rotational axis relative to the plane of Earth’s orbit around the Sun.
3. Variations in the eccentricity
Explanation:
These variations listed above; the precession of the equinoxes (refers, changes in the timing of the seasons of summer and winter), this occurs on a roughly about 26,000-year interval; changes in the tilt angle of Earth’s rotational axis relative to the plane of Earth’s orbit around the Sun, this occurs roughly in a 41,000-year interval; and changes in the eccentricity (that is a departure from a perfect circle) of Earth’s orbit around the Sun, occurring on a roughly 100,000-year timescale. which influences the mean annual solar radiation at the top of Earth’s atmosphere.
Oneiididudd even said wy the candy shop in the candy store and you I know you got it to get your gift card owywiwywuwywywywtwtwtwtwt teteyy gift cards and gift card gift gift card for your card gift cards to you
GPE I am assuming is gravitational potential energy. I'll denote it as U for simplicity.
U = mgy
U = (70kg)(9.81m/s^2)(1m) = 686.7J
U = 686.7J
Hope this helps!