Explanation:
To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;
Be = 2, 2
F = 2, 7
Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.
When Be loses two electrons it becomes isoelectronic with He;
Be → Be²⁺ + 2e⁻
Also, when fluorine gains an electron, it becomes isoelectronic with Ne;
F + e⁻ → F⁻
This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.
Hence;
Be²⁺ + 2F⁻ → BeF₂
Answer:
Laboratories use both distilled water and deionized water as controls in experiments. Deionization removes only non-charged organic matter from the water.
Explanation:
Distilled water removes even more impurities than deionization does, if the water undergoes a filtering process before boiling and distillation.
I’m pretty sure it’s the second answer B
Answer:
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