Question

How many atoms of Ca are in 4.7 moles of calcium?

Answer 1

Answer: There are $28.303 \times 10^{23}$ atoms in 4.7 moles of calcium.

Explanation:

According to Avogardo's number for every 1 mole of a substance there will be $6.022 \times 10^{23}$ atoms.

For the given Ca atom there are 4.7 moles. Hence the number of atoms present in 4.7 moles will be calculated as follows.

         Moles present = $4.7 \times 6.022 \times 10^{23}$ atoms

                                  = $28.303 \times 10^{23}$ atoms

Thus, we can conclude that there are $28.303 \times 10^{23}$ atoms in 4.7 moles of calcium.