Answer:
K = 0,00000135 = 1.35 * 10^-6
Explanation:
Step 1: Data given
The equilibrium constant, K, for any reaction is defined as the concentrations of the products raised by their coefficients divided by the concentrations of the reactants raised by their coefficients. In this case, the concentrations are given as partial pressures.
The partial pressures of H2O = 0.0500 atm
The partial pressures of H2 = 0.00150 atm
The partial pressures of O2 = 0.00150 atm
Step 2: The balanced equation
2H2O(g) ⇆ 2H2(g) + O2(g)
Step 3: Calculate K
K = [O2][H2]² / [H2O]²
K = 0.00150 * 0.00150² / 0.0500²
K = 0,00000135 = 1.35 * 10^-6
Percentage yield= (actual/theoretical)x100
So in this case the actual yield is 110 and the theoretical yield is 125.
So you would do =(110/125)x100
So the answer would be =88%
Balance Chemical Equation is,
<span>CaO </span>₍s₎ <span>+ CO</span>₂ ₍g₎ <span>→ CaCO</span>₃ ₍s₎
According to Equation
56.07 g of CaO when reacted with excess CO₂ produces = 100.08 g of CaCO₃.
Then,
1.8 g of CaO is reacted with excess CO₂ = X g of CaCO₃ will produce.
Solving for X,
X = (100.08 g × 1.8 g) ÷ 56. 07 g
X = 3.21 g of CaCO₃