Explanation:
The given data is as follows.
Mass of ice dropped = 325 g
Initial temperature =
= (30 + 273) K = 303 K
Final temperature =
= (0 + 273) K = 273 K
Now, using density of water calculate the mass of ice as follows.

= 500 g
As the relation between heat energy, specific heat and change in temperature is as follows.
Q = 
= 
= 62750 J
Also, relation between heat energy and latent heat of fusion is as follows.
Q = m L
= 
= 108300 J
Therefore, we require
heat but we have 40774.95 J.
So, 
=
= 188.4 g
Hence, the mass of ice = 325 g - 188.4 g
= 137 g
Therefore, we can conclude that 137 g of ice will still be present when the contents of the pitcher reach a final temperature.
1. False
2. False
3. True
4. True
5. True
<span>Volume = pir^2h = 36pih
Derivative = 36pi dh/dt
v' = 2 m^3/min
2 = 36pi dh/dt
dh/dt = 0.0177 m/min.</span>
Le Chatelier's principle states that when a change is brought to a system in equilibrium, the equilibrium will shift in a manner to reverse that change.
If the pressure is increased, the system will try to reduce the pressure. The only way it can do this is by producing less gas. Therefore, shifting the equilibrium to the left. Thus, the statement is true.