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asambeis [7]
3 years ago
6

What are some of the important funtions of cells

Chemistry
1 answer:
rosijanka [135]3 years ago
7 0
In biological terms a cells main purpose is to survive but some important functions of cells are 1. Transports ( of molecules) 2. Chemical Reactions ( I.e Metabolism ) including energy conversion 3. reproduction hope this helps!
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A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the ca
BaLLatris [955]

Answer: The density of the liquid is 1.10g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of the unknown liquid  = 938 grams

Volume of the unknown liquid = 0.852L=852cm^3  (1L=1000cm^3

Putting in the values we get:

Density=\frac{938g}{852cm^3}

Density=1.10g/cm^3

Thus the density of the liquid is 1.10g/cm^3 and the liquid is dimethyl sulfoxide.

8 0
3 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
3 years ago
Mothballs are composed primarily of the hydrocarbon naphthalene (C10H8). When 1.025 g of naphthalene is burned in a bomb calorim
Serggg [28]

Answer:

\Delta E_{rxn} for combustion of naphthalene is -5164 kJ/mol

Explanation:

\Delta E_{rxn}=C_{calorimeter}\times \Delta T_{calorimeter}

where, C refers heat capacity and \Delta T refers change in temperature.

Here, \Delta T_{calorimeter}=(32.33-24.25)^{0}\textrm{C}=8.08^{0}\textrm{C}

So, \Delta E_{rxn}=(5.11\frac{kJ}{^{0}\textrm{C}})\times (8.08^{0}\textrm{C})=41.3kJ

\Delta E_{rxn} is generally expressed in terms of per mole unit of reactant. Also, \Delta E_{rxn} should be negative as it is an exothermic reaction (temperature increases).

Molar mass of naphthalene is 128.17 g/mol

So, 1.025 g of naphthalene = \frac{1.025}{128.17}moles of naphthalene

                                              = 0.007997 moles of naphthalene

\Delta E_{rxn}=-\frac{41.3kJ}{0.007997mol}=-5164kJ/mol

5 0
3 years ago
Which characteristic of water helps it form strong bonds with other water molecules?
Vladimir79 [104]

The polar characteristic of water helps it form strong bonds with other water molecules.

<h3>What is polar structure?</h3>

A polar molecule is a molecule in which one end of the molecule is slightly positive, while the other end is slightly negative.

The attractive force between water molecules is a dipole interaction.

The hydrogen atoms are bound to the highly electronegative oxygen atom (which also possesses two lone pair sets of electrons, making for a very polar bond).

Hence, option D is correct.

Learn more about polar bonds here:

brainly.com/question/10777799

#SPJ2

5 0
2 years ago
Read 2 more answers
Calculate the molarity of a NaOH solution that is prepared by diluting 100mL of 0.20M NaOH with 150mL of H2O.
lianna [129]

Molarity of solution = 0.08 M

<h3>Further explanation  </h3>

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution  

\tt M=\dfrac{n}{V}  

Where  

M = Molarity  

n = number of moles of solute  

V = Volume of solution  

  • mol of NaOH

\tt mol=0.2~M\times 100~ml=20~mlmol=0.02~mol

  • molarity

Volume of solution = 100 ml + 150 ml = 250 ml

\tt M=\dfrac{0.02~mol}{0.250~L}=0.08

3 0
3 years ago
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