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Svet_ta [14]
3 years ago
5

What are the first three common multiples of 18 and 30?In class need help now!

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0
All the multiples of 18 and 30
18: 1,2,3,6,9,18
30: 1,2,3,5,6,10,30
The first three common ones are: 1,2 and, 3
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√48a^4 b^5 c^3 d simplify and keep it in radical form
Morgarella [4.7K]
I will assume the square root extends all the way across.

\sqrt{48a^4b^5c^3}

\sqrt{2^4\cdot3\cdot a^4b^5c^3}

\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}

4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}

\boxed{4a^2b^2c\sqrt{3bc}}






3 0
3 years ago
Classify each pair of labeled angles as complementary, supplementary, or neither.
professor190 [17]
Supplementary, complementary, neither
6 0
3 years ago
Which expressions represents twelve diminished by six times a number:. 12-6n; 6n-12; 12n-6
Ede4ka [16]
12-6n
.......................
4 0
3 years ago
Read 2 more answers
\angle1=9x+5 what is angle 1?
Archy [21]

Answer:

x = -5/9

Step-by-step explanation:

9x + 5 = 0

x = -5/9

if this is incorrect then ur question is missing something

3 0
2 years ago
Math help @LIEMONDER
klio [65]
First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)
5 0
3 years ago
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