Answer:
<h2>C.</h2>
Step-by-step explanation:
The equationof a circle:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
<em>(h, k)</em><em> - center</em>
<em>r</em><em> - radius</em>
<em />
We have <em>center = (4, -1) → h = 4, k = -1</em>, and <em>r = 9</em>.
Substitute:
![(x-4)^2+(y-(-1))^2=9^2\\\\\huge\boxed{(x-4)^2+(y+1)^2=81}](https://tex.z-dn.net/?f=%28x-4%29%5E2%2B%28y-%28-1%29%29%5E2%3D9%5E2%5C%5C%5C%5C%5Chuge%5Cboxed%7B%28x-4%29%5E2%2B%28y%2B1%29%5E2%3D81%7D)
A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
135
Step-by-step explanation:
15 x 9 = 135
What I got was 9/10 or you could make it into a percentage 90% hope this helps