I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
13 feet wide.
156/12=13
Brainliest plz
Answer: B. 200ft
Step-by-step explanation:
Pythagorean theorem so a^2+b^2+c^2 or 120^2+160^2=c^2 where c is the value for the diagonal so solving for c to get 200
Answer:
PQ = 5 units
QR = 8 units
Step-by-step explanation:
Given
P(-3, 3)
Q(2, 3)
R(2, -5)
To determine
The length of the segment PQ
The length of the segment QR
Determining the length of the segment PQ
From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.
so
P(-3, 3), Q(2, 3)
PQ = 2 - (-3)
PQ = 2+3
PQ = 5 units
Therefore, the length of the segment PQ = 5 units
Determining the length of the segment QR
Q(2, 3), R(2, -5)
(x₁, y₁) = (2, 3)
(x₂, y₂) = (2, -5)
The length between the segment QR is:




Apply radical rule: ![\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)

Therefore, the length between the segment QR is: 8 units
Summary:
PQ = 5 units
QR = 8 units