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katovenus [111]
3 years ago
7

On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did thei

r average speed change from first to second day, if on the second day they were hiking for 20% longer time?
Mathematics
2 answers:
stira [4]3 years ago
7 0

Answer:

Step-by-step explanation:

TRY TO SOLVE THIS

On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did their average speed change from first to second day, if on the second day they were hiking for 20% longer time

finlep [7]3 years ago
6 0
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day. 
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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