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katovenus [111]
3 years ago
7

On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did thei

r average speed change from first to second day, if on the second day they were hiking for 20% longer time?
Mathematics
2 answers:
stira [4]3 years ago
7 0

Answer:

Step-by-step explanation:

TRY TO SOLVE THIS

On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did their average speed change from first to second day, if on the second day they were hiking for 20% longer time

finlep [7]3 years ago
6 0
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day. 
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Answer:

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Step-by-step explanation:

The equation in two variables that can be used to represent the situation given can be determined using computer software such Stat-Crunch or Ms. Excel or advanced calculators.

I shall use Ms. Excel for this question.

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Click anywhere inside the chart, then select the design tab under chart tools. Click on the Add Chart element in the upper left corner of the excel workbook and select more trend-line options. This feature will enable us to fit any trend-line to our data.

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Find the attached.

The equation in two variables is thus;

y=256e^{-0.288x}

5 0
3 years ago
In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse. If b = 77 centimeters and c = 85
MAVERICK [17]

Answer:

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Step-by-step explanation:

Given that,

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Step-by-step explanation:

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