12 The value of x must be greater than a .0 B.1 C.3 D.7

Mathematics

1 answer:

Likurg_2 [28]3 years ago

7 0

Answer:

must be greater than 7

Step-by-step explanation:

using pythagoras theorem

a^2=b^2-c^2

x^2=15^2-12^2

x^2=225-144

x^2=81

take square root both sides

√x^2=√81

x=9

and 9 is greater than 7

You might be interested in

A rectangular pool has dimensions of 40 ft. and 60 ft. The pool has a patio area around it that is the same width on all sides.I

ladessa [460]

Area of pool edge = Area of big rectangle - Area of the pool

Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²

2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800

Length × width = 4800

From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.

We also need the width of the big rectangle to be [[x + x] more than the width of the pool.

Length = 60 + 2x
Width = 40 + 2x

Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]

x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10

We can only use the positive value of x since the context is length

Hence, x = 60