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jeka94
2 years ago
5

12 The value of x must be greater than a .0 B.1 C.3 D.7

Mathematics
1 answer:
Likurg_2 [28]2 years ago
7 0

Answer:

must be greater than 7

Step-by-step explanation:

using pythagoras theorem

a^2=b^2-c^2

x^2=15^2-12^2

x^2=225-144

x^2=81

take square root both sides

√x^2=√81

x=9

and 9 is greater than 7

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I am donating packages for Christmas drive. After the first week, I spent 126 to donate three children packages and 8 adult pack
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Answer:

Step-by-step explanation:

Let the price for children and adults package be represented with x and y respectively.

For the first week the sum of the package will be as follows:

3x+8y = 126

For the two weeks after:

6x+4y= 108

So, we will be having two equations

3x+8y = 126..... (1)

6x+4y= 108.......(2)

These are simultaneous equations

From equation 1

3x+8y = 126

3x = 126-8y

X = 126-8y/3 ............. (3)

Put equation 3 into 2

6 ( 126-8y)/3 +4y = 108

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Cross multiplying

756-48y+12y= 108×3

756-48y+ 12y = 324

Collecting like terms

756-324 = 48y-12y

432= 36y

Divide both sides by 36

432/36 = 36y/36

y= 12

Substituting y into equation 1

3x+8= 126

3x+96=126

3x= 126-96

3x= 30

Divide both sides by 3

3x/3 = 30/3

x = 10

Hence for each of the packages for children and adults. It will be 10 and 12 respectively.

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