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3 years ago

Help please.......Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

Mathematics

1 answer:

maxonik [38]3 years ago

4 0

Answer:

The cost of 1 dozen doughnut is $6 and the cost of a dozen croissant is $10.

Step-by-step explanation:

We know that:

D = Cost of a dozen doughnut
C = Cost of a dozen croissant
10D + 7C = 130
6D + 4C = 76

Work:

10D + 7C = 130

6D + 4C = 76

4(10D + 7C = 130)

7(6D + 4C = 76)

40D + 28C = 520

42D + 28C = 532

40D - 42D = 520 - 532
=> -2D = -12
=> 2D = 12
=> D = 6

Now, let's substitute the value of D into the first equation.

10D + 7C = 130
=> 10(6) + 7C = 130
=> 60 + 7C = 130
=> 7C = 70
=> C = 10

Hence, the cost of 1 dozen doughnut is $6 and the cost of a dozen croissant is $10.

Hoped this helped.

$BrainiacUser1357$

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3 years ago

Byron can fill a drying rack with dishes in 15 minutes. While Byron fills the drying rack, Emmitt takes dishes out of the drying

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Answer:

Hi!

The correct answer is d) 1 over 15 minus 1 over x equals x over 35.

Step-by-step explanation:

We know the amount of time that Byron can fill a drying rack with dishes: 15 minutes.

We know the amount of time that Byron can fill a drying rack with dishes while Emmitt is taking dishes out of the drying rack: 35 minutes.

We don't know the amount of time that Emmitt can take dishes out of the drying rack: x minutes.

So, if Byron is filling the drying rack in 15 minutes and Emmitt is taking out the dishes at x minutes, it takes 35 minutes to fill the drying rack.

$\frac{1}{15}-\frac{1}{x} = \frac{1}{35}$ // multiply by 105x both sides.

$105x\frac{1}{15}-105x\frac{1}{x} =105x \frac{1}{35}$ // simplifly

$7x - 105 = 3x$ //substract 3x and add 105 in both sides

$7x - 3x - 105 + 105 = 3x - 3x + 105$ // solve

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3 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

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As take B(11, 3) to C (11, 9).

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As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

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AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

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Breadth = 6 units

Put value in the above

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Therefore the area of a rectangle is 42 units ².

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3 years ago

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