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3 years ago

Which of the following best describes the equation below? y = 5x - 15

Mathematics

2 answers:

ddd [48]3 years ago

8 0

The answer is d because 3x5=15

Tanzania [10]3 years ago

7 0

Answer:

D linear

Step-by-step explanation:

We can tell pretty easily that this is a linear equation. How? Look at the highest degree of x!

This means the highest exponent of x. It looks like we have 5x, which you can think of as 5x to the first power. Whenever the highest exponent is 1, the equation is linear.

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NO ONE EVER ANSWERS MY QUESTIONS I NEED HELP PLEASE!!! 2 problems Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM. a

almond37 [142]

To solve this problem we will use sinus theorem.

It's general form is

a/sinα = b/sinβ = c/sinγ

In this case it reads ML/sin∡K = KL/sin∡M = KM/sin∡L =>

ML/sin∡K = KL/sin∡M => 12/sin60° = KL/sin45° => 12/(√3/2) = KL/(√2/2) =>

2*12/√3 = 2*KL/√2 => We will divide whole equation with number 2 and get

12/√3=KL/√2 => KL*√3=12√2 => KL=(12√2)/√3

When we rationalize denominator we get KL=4√6≈ 4*2.45= 9.8

Considering that we know two angles we will calculate the third

∡K+∡M+∡L=180° => 60°+45°+∡L=180° => ∡L= 180-105=75°

Reason- The theorem of the sum of the inner angles of the triangle

ML/sin∡K=KM/sin∡L => 12/sin60°=KM/sin75°

We will calculate sin75° = sin (30+45)= sin30 *cos45+cos30*sin45 =>

sin75°= 1/2 * √2/2 = √3/2 * √2/2= √2/4 *(√3+1)≈(1.41/4)*(1.73+1)=0.96

12/(√3/2)=KM/0.96 => 12*2/√3=KM/0.96 => 13.87=KM/0.96 =>

KM=13.87*0.96= 13.31

Perimeter of ΔKLM => P=KL+ML+KM= 12+9.8+13.31= 35.11

In the same way you can calculate perimeter of ΔMNO.

Good luck!!!

4 0

3 years ago

Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar

Mamont248 [21]

Answer:

The 95% confidence interval is

$0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

$n = 125 \ stores$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The number of stores that had more than 2 items price incorrectly is k = 52

Generally the sample proportion is mathematically represented as

$\^ p = \frac{ k }{ n }$

=> $\^ p = \frac{ 52 }{ 60 }$

=> $\^ p = 0.867$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.867 (1- 0.867)}{60} }$

=> $E = 0.0859$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.867 - 0.0859 < p < 0.867 + 0.0859$

=> $0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Considering question b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

Considering question c

From the question we are told that

The margin of error is E = 0.05

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$