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3 years ago

Find the sum of (x + 5) and (2x + 3)

Mathematics

2 answers:

weeeeeb [17]3 years ago

8 0

Answer:

3x+8

Step-by-step explanation:

Arte-miy333 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

$\left(x+5\right)+\left(2x+3\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=x+5+2x+3\\\\\mathrm{Group\:like\:terms}\\=x+2x+5+3\\\\\mathrm{Add\:similar\:elements:}\:x+2x=3x\\=3x+5+3\\\\=3x+8$

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Greg withdrew $37 from his account on Wednesday and then deposited $15 in his account on Thursday. On Friday, he withdrew $120.

barxatty [35]

he had $297 in his account before wednesday

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3 years ago

19. Find the current in a circuit if the power is 500 W (watts) and the resistance is 25 ohms. Round off your answer to two deci

HACTEHA [7]

Answer:

Step-by-step explanation:

The formula that relates current, power and resistance is

$I=\sqrt{\frac{P}{R}}$

Where

I is the current (in amperes)

P is the power (in watts)

R is the resistance (in ohms)

We know P = 500 and R = 25, we plug them into the formula and solve for I:

$I=\sqrt{\frac{P}{R}}\\I=\sqrt{\frac{500}{25}}\\I=\sqrt{20}\\ I=4.47$

Correct answer is 4.47 Amperes, or choice A.

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3 years ago

Assume log bx = 0.49. Evaluate.<br> Logbx^2

Snowcat [4.5K]

Step-by-step explanation:

Use exponent property of logs.

logb(x²) = 2 logb(x) = 2(0.49) = 0.98

8 0

3 years ago

I'm pretty sure this is easy for some of you but not me!

saw5 [17]

Answer:

The possible outcomes are H1, H2, T1, and T2

Step-by-step explanation:

You can result in Heads and one, Heads and two, Tails and one, or Tails and two. Hope this helps!

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3 years ago

A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s

yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

$x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2} = \frac{1 \pm 9 }{-0.4}$

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0

2 years ago