Question

Which pair of triangles can be proved congruent by the SAS Postulate?

Answer 1

I think its A the first one

Answer 2

Answer: $A.\ \triangle{ABX}\cong\triangle{DEX}$

Step-by-step explanation:

In the given picture , we have given that X is the midpoint of $\overline{AD}$ and $\overline{BE}$ .

i.e. AX = XD and BX=XE               (1)

Then in $\triangle{ABX}$ and $\triangle{DEX}$, we have

$\angle{AXB}\cong\angle{EXD}$  [∵ Vertical angles are congruent ]

AX = XD and BX=XE                     [from (1)]

So by SAS postulate of congruence , we have

$\triangle{ABX}\cong\triangle{DEX}$