♥ Solve:
(Arjun) 40*30=1200
(Dalia) 55*30=1650
Now subtract
1650-1200=450.
That means that Dalia will type 450 minutes more.
Final answer: 450
Answer:
x=− 9
/4
or
=−2.250
Step-by-step explanation:
This too hard- i havent learned it yett --.-- sowwyy
Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:


We know that:



Then our integral is:

The right side is equal to:

The bounded area is 5 + 5/6 square units.
6m+1=-23. Do the inverse operation of adding 1 which is to subtract 1 to both sides =====> 6m+1-1= -23-1
You divide by 6 both sides
6m/6=-24/6
m= -4
Brainliest?