Question

A cylindrical swimming pool has a diameter of 16 feet and a height of 4 feet. About how many gallons of water can the pool contain? Round your answer to the nearest whole number. (1 ft³ ≈ 7.5 gal)
To the nearest whole number, the pool can hold gallons of water.

Answer 1

Answer:

107 gal

volume formula of a cylinder is pi * r^2 * h

it gives you the diameter 16 but we need to find the radius. divide it by 2. radius is 8

we already know the height.

pi= 3.14 * 8^2 * 4

3.14 * 64 *4

you find your volume. then divide it by 7.5

Answer 2

Answer:

6032 gallons

Step-by-step explanation:

The diameter of the cylindrical swimming pool is 16 ft

The height(h) of the pool is 4 ft

Volume of a cylinder is given by;

Volume (v) = π × r² × h

Radius (r) = 16/2 ft = 8 ft

v = π × (8 ft)² × 4ft = 804.247719319ft³

Given; 1ft³ = 7.5 gallons (gal)

804.247719319ft³ would equal to how many gallons?

Cross multiplying gives,

$\frac{804.247719319}{1}$ × 7.5 gal = 6031.85789489

Which equals to 6032 gallons rounded up to whole number.