Answer:
Erik's average speed exceeds the speed limit by 6.91 miles per hour.
Step-by-step explanation:
Let suppose that Erik travels at constant speed. Hence, the speed (
), measured in miles per hour, is determined by following equation of motion:
(1)
Where:
- Distance, measured in miles.
- Time, measured in hours.
Please notice that a hour equals 60 minutes. If we know that 
and 
, then the speed of Erik is:
Which is 6.91 miles per hour above the speed limit.
Answer:
For any 2 real numbers all <em>algebric</em><em> </em><em>operations</em><em> </em><em>like</em><em> </em><em>+</em><em>,</em><em>-</em><em>,</em><em>×</em><em>,</em><em>÷</em><em> </em><em>are</em><em> </em><em>defined</em>
Answer:
I think it should be the 1st one
Step-by-step explanation:
sorry if it is wrong hope it helps
Answer:
y = 5 cos ((2π/3)x - 2) + 2
Step-by-step explanation:
Cosine function takes a general form of y = A cos (Bx + C) + D
Where
A is the amplitude
2π/B is the period
C is the phase shift ( if -C, then phase shift right, if +C phase shift left)
D is the vertical displacement (+D is above and -D is below)
Given the conditions of the function to build and the general form, we can write:
** Note: period needs to be 3, so 2π/B = 3, hence B = 2π/3
Now we can write:
y = 5 cos ((2π/3)x - 2) + 2
first answer choice is right.
The correct given equation is:
v = [3 (h + 1)^2.5 + 580 h – 3] / 10 h
So to solve for the instantaneous velocity at t = 1, we
must set h = 0. However we cannot do that since h is in denominator and a
number divided by a denominator is infinite. Therefore we must set h to
something almost zero. In this case, h = 0.0000001, so that:
at t = 1
v = [3 (0.0000001 + 1)^2.5 + 580 (0.0000001) – 3] / 10 *
0.0000001
<span>v = 58.75 ft/s</span>
