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3 years ago

What's the formula for combined law

Physics

1 answer:

ankoles [38]3 years ago

4 0

Answer:

p1 v1 / t1 = p2 v2 / t2 <- Combined Gas Law

Explanation:

p1= first pressure

p2 = second pressure

v1= first volume

v2= second volume

t1= first temperature

t2= second temperature

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a cement block accidentally falls from rest from the ledge of a 80.6-m-high building. When the block is 10.8 m above the ground,

fomenos

Answer:

0.229 seconds

Explanation:

Given:

y₀ = 80.6 m

v₀ = 0 m/s

a = -9.8 m/s²

We need to find the difference in times when y = 10.8 m and y = 2.10 m.

When y = 10.8 m:

y = y₀ + v₀ t + ½ at²

10.8 = 80.6 + (0) t + ½ (-9.8) t²

10.8 = 80.6 − 4.9 t²

4.9 t² = 69.8

t = 3.774

When y = 2.10 m:

y = y₀ + v₀ t + ½ at²

2.10 = 80.6 + (0) t + ½ (-9.8) t²

2.10 = 80.6 − 4.9 t²

4.9 t² = 78.5

t = 4.003

The difference is:

4.003 − 3.774 = 0.229

The man has 0.229 seconds to get out of the way.

5 0

4 years ago

A car has a weight of 25000 N and its brakes can apply a maximum force of 628 N to stop it. The car is initially moving at a spe

svlad2 [7]

Time required : 25.876 s

<h3>Further explanation</h3>

Given

A car weight = 25000 N

Brake force = 628 N

vo= 6.5 m/s

vt = 0(stop)

Required

time to stop

Solution

W = m . g

25000 = m.10

m=2500 kg

Newton's second law

F = m . a

628 = 2500 . a

$\tt a=\dfrac{628}{2500}=0.2512~m/s^2$

vt=vo-at(deceleration a=-)

0=6.5-0.2512.t

0.2512.t=6.5

t=25.876 s

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3 years ago

Two train whistles have identical frequencies of 1.64 102 Hz. When one train is at rest in the station and the other is moving n

Amiraneli [1.4K]

Answer:

Vs = 6.73 m/s or Vs = 16.3 m/s

Explanation:

frequency of the trains whistle (f) = 1.64 x 10^{2} Hz = 164 Hz

frequency of beats heard = 4 beats/s = 4 Hz

velocity of the stationary train (Vr) = 0

velocity of sound in air (V) = 343 m/s

velocity of the moving train (Vs) = ?

we can get the velocity of the moving train from the formula below

Fn = f x $\frac{V + Vr}{V - Vs}$ ...equation 1

where Fn = net frequency

case one - assuming the train is approaching the station Fn = 164 + 4 = 168 Hz

substituting the known values into equation 1

168 = 164 x $\frac{343 + 0}{343 - Vs}$

1.02 = $\frac{343 + 0}{343 - Vs}$

Vs = $343 - \frac{343 + 0}{1.02}$

Vs = 6.73 m/s

case two - assuming the train is leaving the station Fn = 164 - 4 = 160 Hz

substituting the known values into equation 1

168 = 160 x $\frac{343 + 0}{343 - Vs}$

1.05 = $\frac{343 + 0}{343 - Vs}$

Vs = $343 - \frac{343 + 0}{1.05}$

Vs = 16.3 m/s

6 0

4 years ago

Oscilloscope channel addition problem. Read the followingoscilloscope settings carefully. Suppose you display a 1 kHz, 2 Vsine w

Novay_Z [31]

Answer: B. The trace jumps down 1 division

Explanation:

From the above data, the two signals are combined and adjusted in the middle of the screen. If you switch the signal in channel B from DC to AC, then the screen jumps down 1 division.

4 0

4 years ago

What form of matter is "vapor"?

elena55 [62]

Vapor is usually made with water and it would be made with gas.

4 0

4 years ago

What's the formula for combined law​

What's the formula for combined law