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vlabodo [156]
3 years ago
15

What is an example of chemical potential energy in humans?

Physics
1 answer:
Brilliant_brown [7]3 years ago
6 0
During cellular respiration, our bodies take glucose molecules and breaks the bonds holding the molecules together. When these bonds are broken, the chemical energy stored in these bonds are released and used to make ATP molecules, a form of useable energy for us.
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Why was Earth very hot at the beginning of its formation? Select all that apply.
Sladkaya [172]

Answer:

heat came from the supernova that led to the formation of solar system

4 0
3 years ago
A circuit supplied with 110V carries 5 Amps current. Calculate the Resistance value of the circuit?
IgorC [24]

Answer:

The value is R =  22 \  \Omega

Explanation:

From the question we are told that

     The voltage is  V  =  110 \  V

    The current is  I  =  5 \  A

Generally the resistance value is mathematically represented as

         R =  \frac{V}{I}

=>      R =  \frac{110}{5}

=>      R =  22 \  \Omega

6 0
3 years ago
1. An object with a mass of m is thrown straight up near the surface of the earth. While the object is going up, the net force o
Vaselesa [24]

Answer:

C: equal to mg

Explanation:

in free-fall, gravity is always the net force on an object

5 0
3 years ago
What is the maximum range of most handheld fire extinguishers?        A. 50 yd   B. 30 ft   C. 10 ft   D. 100 ft
alex41 [277]
C- 10ft. Hope this helped. Have a great day! :D
5 0
3 years ago
Read 2 more answers
The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various
Schach [20]

Answer:

q  =  -461532.5 \ C

Explanation:

From the question we are told that

     The  electric filed is  E  =  102 \ N/C  

Generally according to Gauss law

=>   E  A  =  \frac{q}{\epsilon_o }

Given that  the electric field is pointing downward  , the equation become

    - E  A  =  \frac{q}{\epsilon_o }

Here   q is the excess charge on the surface of the earth

          A is the surface  area of the of the earth which is mathematically represented as

     A  =  4\pi r^2

Where r is the radius of the earth which has a value r = 6.3781*10^6 m

 substituting values

    A  = 4 * 3.142  *   (6.3781*10^6 \ m)^2

    A  =5.1128 *10^{14} \ m^2

So

   q  =  -E  * A  *  \epsilon _o

Here \epsilon_o s the permitivity of free space with value

          \epsilon_o  =  8.85*10^{-12} \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

     q  =  -102  * 5.1128 *10^{14}  *  8.85 *10^{-12}

     q  =  -461532.5 \ C

6 0
3 years ago
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