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guapka [62]
3 years ago
6

I really need help ! it would mean alot if you did help ❤️ !​

Mathematics
2 answers:
arlik [135]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Hope this helps!!!

Roman55 [17]3 years ago
4 0

Answer:

B. Math , Social Studies , Reading is the answer.

I think this helps you ☺️☺️.

Thank you ☺️☺️☺️

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Extra points and top BRAINIEST!!!<br> An is parallel to DE in the map below
Margaret [11]

Answer:

Third option

Step-by-step explanation:

\frac{9}{6}  =  \frac{15}{x}  \\

is the correct answer.

6 0
3 years ago
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If the scale factor of sides is 3, then the scale factor of area is ___ and the scale factor of
snow_tiger [21]

Answer:

Here is an example: if we have a rectangle that has a length 3 and a height of 4 and the scale drawing with a scale factor of 2, how many times bigger is the scale drawings area? The original shape is 3 by 4 so we multiply those to find the area of 12 square units.

5 0
2 years ago
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Figure 2 was constructed using figure 1. For the transformation to be defined as a rotation, which statements must be true? Sele
Thepotemich [5.8K]

Answer:

The segment connecting the center of rotation, C, to a point on the pre-image (figure 1) is equal in length to the segment that connects the center of rotation to its corresponding point on the image (figure 2).

The transformation is rigid.

Every point on figure 1 moves through the same angle of rotation about the center of rotation, C, to create figure 2.

If figure 1 is located 360° about point C, it will be mapped onto itself.

Step-by-step explanation:

7 0
3 years ago
Solve for n: -1/2 (n + 8) +3/4
vlabodo [156]

\frac{1}{2} (n+8) + \frac{3}{4}

\frac{1(n+8)}{2}  +  \frac{3}{4}

\frac{n+8}{2}  +  \frac{3}{4}

\frac{2(n+8)}{4}  + \frac{3}{4}

\frac{2(n+8) + 3}{4}

\frac{2n + 16 +3}{4}

\frac{2n + 19}{4}

7 0
2 years ago
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
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