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Advocard [28]
3 years ago
15

The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 900 hours and a standard deviation

of 55 hours. Out of 720 freshly installed light bulbs in a new large building, how many would be expected to last between 800 hours and 1030 hours, to the nearest whole number?
Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

Answer: 689

Step-by-step explanation:

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Can someone help me i will give point math please
castortr0y [4]
He worked as a carpenter for 12 hrs. and as a blacksmith for 18.
4 0
3 years ago
Find the ordered pairs for the x- and y-intercepts of the equation 3x - 2y =18
Len [333]
X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
5 0
3 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
4 corners again<br> -9a + 3b - a + 7b - 13 + a - 10<br> Sorry for the questions pls help
eimsori [14]

Answer:−9a+10b−23

Step-by-step explanation:−9a+3b−a+7b−13+a−10

Combine −9a and −a to get −10a.

−10a+3b+7b−13+a−10

Combine 3b and 7b to get 10b.

−10a+10b−13+a−10

Combine −10a and a to get −9a.

−9a+10b−13−10

Subtract 10 from −13 to get −23.

−9a+10b−23

8 0
3 years ago
Read 2 more answers
Solve the equation<br> 6.7x = 5.2x + 12.3
Anna [14]

Answer:

x = 8.2

Step-by-step explanation:

6.7x = 5.2x + 12.3

6.7x - 5.2x = 12.3

1.5x = 12.3

x = 8.2 =  \frac{41}{5}  = 8 \frac{1}{5}

7 0
3 years ago
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