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Advocard [28]
2 years ago
15

The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 900 hours and a standard deviation

of 55 hours. Out of 720 freshly installed light bulbs in a new large building, how many would be expected to last between 800 hours and 1030 hours, to the nearest whole number?
Mathematics
1 answer:
max2010maxim [7]2 years ago
7 0

Answer: 689

Step-by-step explanation:

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Simplify completely:<br> 4V10 – V6 +3710<br> Show all work for full credit.
schepotkina [342]
The answer is 7√10−√6

5 0
3 years ago
One night Puvi spent 1/3 of his money on dinner and then 1/4 of the remaining money on dessert. He then had just enough left so
arsen [322]

Answer:

Step-by-step explanation:

Cost of two tickets = 2 * 30 = £60

Let the amount with Puvi = £x

Money spent on dinner = (1/3)*x

                                        = \dfrac{1}{3}x

Remaining \ money =x -  \dfrac{1}{3}x =\dfrac{3}{3}x-\dfrac{1}{3}x=\dfrac{2}{3}x

Money \ spent \ on \ dessert = \dfrac{1}{4} *\dfrac{2}{3}x =\dfrac{1}{6}x\\\\\\

Total money - money spent on dinner - money spent on dessert = 60

x -\dfrac{1}{3}x -\dfrac{1}{6}x=60\\\\\\\dfrac{6}{6}x-\dfrac{1*2}{3*2}-\dfrac{1}{6}x =60\\\\\\\dfrac{6}{6}x-\dfrac{2}{6}x-\dfrac{1}{6}x=60\\\\\\\dfrac{6-2-1}{12}x=60\\\\\\\dfrac{3}{12}x=60\\\\\\x=60*\dfrac{12}{3}=60*4=240

Money that Puvi had at the start of the night = £ 240

8 0
2 years ago
if the variance of the data values in a population is 256, what is the standard deviation of the data values?
kumpel [21]
The standard deviation is the square root of the variance

so if the variance is 256, then the standard deviation is : sqrt 256 = 16 <==
5 0
3 years ago
The diagram below represent the rate of making copies on a copy machine. Which table represent this rate?
Nuetrik [128]

Answer:

its B

Step-by-step explanation:

6 0
2 years ago
Simplify:
liubo4ka [24]

Answer:

78.5÷3.14=25

56.272×41.2=2318.4064

429×338×712=103241424

447÷513=0.8713450292

Step-by-step explanation:

hope it will help!

8 0
2 years ago
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