Answer:
idek but i get free points hehe
Step-by-step explanation:
Answer:
4y = 6x + 40
Step-by-step explanation:
The general equation of a straight line is y = mx + b
m is the slope and b is the y-intercept
let us write both equations in this form;
we have this as;
6y = -4x + 1
y = -4x/6 + 1/6
and;
2x + 3y = 18
3y = -2x + 18
y = -2x/3 + 6
So firstly we want to find an equation that is perpendicular to the first
When two lines are perpendicular, their slopes has a product of -1
The slope of the first line is -4/6
let the slope of the line we want be m
As per they are perpendicular;
-4/6 * m = -1
-4m/6 = -1
-4m = -6
m = 6/4
So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6
we can choose 10
and we have the equation as:
y = 6x/4 + 10
multiply through by 4
4y = 6x + 40
Cos(x) = 50/100
part a) x= 60°
<span>part b) height is 86.60254040</span>
4(2x+10)= 0
8x+40=0
subtract 40 from both sides
8x+40-40=0-40
8x=-40
x=-40/8
x=-5
4(2x-10)=0
8x-40=0
Add 40 from both sides
8x-40+40=0+40
8x=40
x=40/8
x=5
