<span>Write the equation of the line that satisfies the given conditions, Express the final equation in standard form. Contains the point (2,5) and is parallel to the line x-2y=-5
The given equation can be written 2y=x+5; y = (1/2)x+(5/2)
It's slope is 1/2
So any line parallel to it has slope = 1/2
If the line also passes thru (2,5), 5 = (1/2)2+b; b=4
Therefore the equation you want is y = (1/2)x+4</span>
Step-by-step explanation:
90.......................
X^2 + y^2 - 2x + 7y + 1 = 0
(x^2 - 2x) + (y^2 + 7y) + 1 = 0
(x^2 - 2x + 1) + (y^2 + 7y) + 1 = 0+1
(x^2 - 2x + 1) + (y^2 + 7y + 49/4) + 1 = 0+1+49/4
(x - 1)^2 + (y + 7/2)^2 + 1 = 0+1+49/4
(x - 1)^2 + (y + 7/2)^2 + 1-1 = 0+1+49/4-1
(x - 1)^2 + (y + 7/2)^2 = 49/4
(x - 1)^2 + (y + 7/2)^2 = (7/2)^2
The final answer is choice B
It's rigged
The vertical line test can be used to determine whether a graph represents a function
