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krek1111 [17]
3 years ago
15

Which pair or pairs of polygons are congruent?

Mathematics
2 answers:
nlexa [21]3 years ago
6 0
I believe tye answer is C
svlad2 [7]3 years ago
4 0

Answer: the answer is B

Step-by-step explanation:

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Marco Has a peice of wood that measures 9x1/10 + 6x1/100 + 4 x 1/1000 meter. How can this measurement be written as a decimal
grin007 [14]
The answer is 0.964
7 0
4 years ago
Gwent pour 256 milliliters of water in to Ravi Henry pours 189 milliters of water in to Ravis .Ravis now contains 800 Milliters
Contact [7]

Answer:

Ravi had 355ml water to begin with.

Step-by-step explanation:

Given that,

amount of water that Gwent pour in Ravi = 256 ml

amount of water that Henry pour in Ravi = 189 ml

amount of water after each have poured = 800 ml

suppose amount of water ravi had before both poured water in it = x

Equation

256 + 189 + x = 800

445 + x = 800

x = 355ml

Initially ravi had 335ml of water.

6 0
4 years ago
Assume that each circle shown below represents one unit. Express the shaded amount as a single fraction and as a mixed number.
poizon [28]

Answer:

one fraction 17/5

mixed number: 3 2/5

Step-by-step explanation:

4 0
3 years ago
8 1/2 minus 7 1/4 in fraction form?
barxatty [35]

Answer:

1  1/4

1.25

Step-by-step explanation:

8 0
3 years ago
If f(x)=x+7 and g(x)= 1 divided by x-13, what is the domain of (f•g)(x)?
andrew11 [14]
<h2>Hello!</h2>

The answer is:

The domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

<h2>Why?</h2>

This is a composite function problem. To solve it, we need to remember how to composite a function. Composing a function consists of evaluating a function into another function.

Composite function is equal to:

f(g(x))=(f\circ} g)(x)

So, the given functions are:

f(x)=x+7\\\\g(x)=\frac{1}{x-13}

Then, composing the functions, we have:

f(g(x))=\frac{1}{x-13}+7\\

Therefore, we must remember that the domain are all those possible inputs where the function can exists, most of the functions can exists along the real numbers with no rectrictions, however, for this case, there is a restriction that must be applied to the resultant composite function.

If we evaluate "x" equal to 13, the denominator will tend to 0, and create an indetermination since there is no result in the real numbers for a real number divided by 0.

So, the domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

Have a nice day!

5 0
3 years ago
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