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borishaifa [10]
3 years ago
11

For f(x) = 4x + 1 and g(x) = x2 – 5, find (f – g)(x).

Mathematics
2 answers:
Pie3 years ago
6 0
Hey there! How are you today?

First, let's understand what we're doing.
We are dealing with subtracting functions.
Always be sure to know what you're subtracting by what - you don't want to misinterpret the situation and mess up over a minor error.

Now, let's get to the problem.

f(x) = 4x + 1
g(x) = x^2 - 5

Find (f - g)(x).

By "Find (f - g)(x)", we mean to subtract f(x) by g(x).

Remember what f(x) is and what g(x) is.

So, let's set up our equation.

4x + 1 (Remember to subtract like-terms)
-x^2 + 5
——————
-x^2 + 4x + 6 is your solution.

Answer choice "D.)" matches our solution.

I hope this helps!
zavuch27 [327]3 years ago
6 0

Answer:

it is C

Step-by-step explanation:

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It’s already linear ?
8 0
3 years ago
What is the quotient (2x3 − 15x2 − 10x + 16) ÷ (x − 8)? 2x2 − x − 2 2x2 + x + 2 2x2 − x + 2 2x2 + x − 2?
Vedmedyk [2.9K]
(2x³ - 15x² - 10x + 16)/(x - 8)
You can use long division or synthetic division. (I used synthetic division below)

8║2  -15  -10  +16
  ║     16     8   -16
     2    1     -2    0 → 2x² + x - 2

Answer: D
8 0
3 years ago
What is the range of the function graphed below?
aleksandrvk [35]

Answer:       B.     [–4, 0)  ∪  [2, ∞)

To find the range, find out what y-values are possible for the function in the graph.

<h2>Symbols</h2>

We need to pay attention to what symbols to use.

<h3>Reading the diagram</h3>

Solid circle

  • The function touches the point.

Empty circle

  • The function gets close, but does not touch the point.

Arrow

  • The function keeps going to infinity.

<h3>Writing range in set notation</h3>

Square brackets: [ and ]

  • These show that the function touches the point.

Curved brackets: ( and )

  • These show that the function gets close but does not touch the point.
  • Infinity always uses a curved bracket.

Union of sets: ∪

  • This symbol shows that sets of values are talking about the same thing. It's almost like the word 'and'.

<h2>Finding the range of the graphed function</h2><h3>Lower blue line</h3>

Let's start by looking for the lowest possible y-value at the bottom of the diagram. On the graph, the point (4, –4) marked with a solid circle.

The function touches the point and stops. Since the y-value is –4, the lowest possible y-value is:     -4

If we follow the blue line upwards, we find an empty circle at (0, 0). The y-value in (0, 0) is 0. This means that the function gets close, but does not include:     0

So, the first part of our range is:

  • [–4, 0)

<h3>Upper blue line</h3>

The blue line on the top starts where y = 2 at a solid circle. So, the function includes the y-value:    2

If we follow this blue line upwards, it ends with an arrow. This means it will keep going to infinity, which is the symbol:    \infty

So, the second part of our range is:

  • [2, ∞)

<h2>Putting it together</h2>

Put the lower and upper blue lines together with the union of sets symbol. The range is expressed as:    [–4, 0)  ∪  [2, ∞)

Learn more about domain and range here:

brainly.com/question/20349151

4 0
2 years ago
Hi!
solniwko [45]

Answer:

y = 1x - 4

Step-by-step explanation:

You have to solve for the x intercept on the equation

2x-5y=8\\2x-5(0)=8\\2x=8\\x=4\\(4,0)

That is the x intercept for that equation.

Then solve for the y intercept on the equation

4x-3y=12\\4(0)-3y=12\\-3y=12\\y=-4\\(0,-4)

That is the x intercept for that equation.

Use that to find slope for point slope form

\frac{y_{2}-y_{1}}{x_{2}-_{1}} \\\\\frac{-4-0}{0-4} \\\\\frac{-4}{-4} \\\\1

1 is the slope

and slope makes B the y intercept so the equation is

y = 1x - 4

8 0
3 years ago
Can someone answer this please
choli [55]
The awenser of the problem is A
5 0
3 years ago
Read 2 more answers
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