The ages of the 32 recruits in police academy are normally distributed with a mean of 27 with a standard deviation of 2. What pe
rcent of the recruits are between ages 23 and 27?
1 answer:
Z scores are (age - mean) / std dev
= 23 - 27 / 2 = -2 and 27-27 / 2 = 0
Using the standard normal tables we find the required percentage is 47.73%
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