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anastassius [24]

4 years ago

8

A rabbit population is modeled by y = 20/1+4e^-0.5t, where y is the number of rabbits after t months. How many rabbits were ther

e initially?
1
4
20
50

2 answers:

Dmitry_Shevchenko [17]4 years ago

8 0

Answer:

It's B 4

Step-by-step explanation:

i just took the test

liubo4ka [24]4 years ago

3 0

Answer:

4

Step-by-step explanation:

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Find the miles per second traveled if one travels 40 miles in 4 hours.

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$\dfrac{40 \textrm{ miles}}{4 \textrm{ hours}} \times \dfrac{1 \textrm{ hour}}{60 \times 60 \textrm{ seconds}} = \dfrac{1}{360} \textrm{ miles per second}$

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Jersey village population in 1950 was 10,173. The population increases by 8.9% every 10 years. Predict the population in 2020

Oksanka [162]

Answer:

Future Value= 18,478 people

Step-by-step explanation:

eGiving the following information:

Present value (PV)= 10,173

Growth rate (g)= 0.089 every 10 years

Number of periods (n)= 7

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3 years ago

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Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?

lys-0071 [83]

Answer:

$cotg(\theta) = -\frac{12}{35}$

Step-by-step explanation:

The cotangent of theta is:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

$sec(\theta) = \frac{1}{\cos{\theta}}$

In this question

$sec(\theta) = -\frac{37}{12}$

So

$-\frac{37}{12} = \frac{1}{\cos{\theta}}$

Using cross multiplication

$-37\cos{\theta} = 12$

$37\cos{\theta} = -12$

$\cos{\theta} = -\frac{12}{37}$

Now we apply the following trigonometric identity:

$\sin{\theta}^{2} + \cos{\theta}^{2} = 1$

$\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1$

$\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}$

$\sin{\theta}^{2} = 1 - \frac{144}{1369}$

$\sin{\theta}^{2} = \frac{1369 - 144}{1369}$

$\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}$

Since the angle is in the second quadrant, the sine is positive.

$\sin{\theta} = \frac{35}{37}$

Finally, the cotangent:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

$cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}$

$cotg(\theta) = -\frac{12}{35}$

4 0

4 years ago

Read 2 more answers