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exis [7]
3 years ago
15

What is 5 + 2 ? 51/2 + 21/7

Mathematics
2 answers:
Ghella [55]3 years ago
8 0
Well 5+2 is 7 and 51/2+21/7 is 57/2
Degger [83]3 years ago
7 0
5+2=7
51/2 + 21/7 = 357/14 + 42/14 = 399/14
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Find the volume of a cone with a base radius of 6 yd and a height of 9 yd
Veronika [31]
\text {Volume =}  \dfrac{1}{3}  \pi  r^{2} h

\text {Volume =}  \dfrac{1}{3}  \pi  (6)^{2} (9)

\text {Volume =}  339.29 \ yd^3
8 0
3 years ago
The formula=A+2lh+2wh gives surface area a. Of a rectangler solid with length, width, and height, L,W, and H, respectively solve
iogann1982 [59]

Answer:

l= \frac{A}{2h} -w

Step-by-step explanation:

The question is not correct (particularly the expression for the area)

 A=2lh+2wh

Now we are expected to solve for l, that is we are going to make l subject of the formula, we have

let us take the second term on the RHS to the LHS

A-2wh= 2lh

we can now divide both sides by 2h we have

\frac{A-2wh}{2h} = l\\\\l=\frac{A}{2h} -\frac{2wh}{2h} \\\\l= \frac{A}{2h} -w

hence the expression for the length is  l= \frac{A}{2h} -w

6 0
3 years ago
Which functions are symmetric with respect to the y-axis? Check all that apply.
xenn [34]

Answer:

f(x) = |x|, f(x) = [x] + 6

Step-by-step explanation:

Almost all of these are absolute values equations, which means the y doesn't change if x is positive or negative. The first one is the parent form, which is the simplest equation of the absolute equation, so it's symmetric with respect to the y-axis. The second equation is translated 3 units to the left, and the third is translated 31 to the left. The forth is translated 6 up, so it's still symmetric with respect to the y-axis. The fifth is translated 61 units left, and the last one is simply a line, which isn't symmetric.

4 0
3 years ago
Sin0=12/37 find tan0
alexira [117]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

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5 0
3 years ago
Bag of candy contains 4 strawberry
Andreas93 [3]

There are 9 candies in total, with 5 being orange. Think of it. For the first grab, you have a 5/9 chance of it being orange flavored. Now there are 4 orange flavored candies, and 8 total candies in the bag. Grabbing a second candy, Billy has a 4/8 chance of grabbing an orange flavored candy. So your two fractions are...

5/9, 4/8

Can you combine these two fractions for a final answer?

3 0
3 years ago
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