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exis [7]
3 years ago
15

What is 5 + 2 ? 51/2 + 21/7

Mathematics
2 answers:
Ghella [55]3 years ago
8 0
Well 5+2 is 7 and 51/2+21/7 is 57/2
Degger [83]3 years ago
7 0
5+2=7
51/2 + 21/7 = 357/14 + 42/14 = 399/14
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Solve the triangle A=21 C=105 c=5
gregori [183]

Answer:

Granted that uppercase letters are the angles measurements and lowercase letters are the side lengths. I also was unable to round as I don't know to what decimal you need to round to.

First to find the measure of angle B, we must subtract A and C from 180

180-21-105=54

B=54

Next, we can use the law of sines in order to find the measures of a and b

As a reminder, The law of sines is

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

First, lets solve for b

\frac{b}{sin54}=\frac{5}{sin105} \\\\b=\frac{(5)sin54}{sin105}\\\\b=4.187780119

Next lets solve for a

\frac{a}{sin21}=\frac{5}{sin105} \\\\a=\frac{(5)sin21}{sin105}\\\\a=1.85504901

3 0
3 years ago
Need to know the population in 2015
Margarita [4]
\bf P=1110.9e^{kt}\quad 
\begin{cases}
P=1200 &\textit{in thousands}\\
t=2 &\textit{in 2002}
\end{cases}\implies 1200=1110.9e^{k2}
\\\\\\
\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k
\\\\\\
\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\
-------------------------------\\\\

\bf P=1110.9e^{0.0386t}\qquad 
\begin{cases}
t=14\\
\textit{year 2015}
\end{cases}\implies P=1110.9e^{0.0386\cdot 14}
\\\\\\
P\approx 1907.0747\implies about\ 1,907,075\textit{ once rounded up}
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2 years ago
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tensa zangetsu [6.8K]

Answer:

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Step-by-step explanation:

Since the y intercept is the only number without a varible you choose the ones that are the same

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2 years ago
10 question please you don't have to do all I need help
andre [41]

Answer

I'm sorry for not being able to help you but this kind of contents are not allowed ߷߷

8 0
3 years ago
Where is the mistake​
Sphinxa [80]

Answer:

..

Step-by-step explanation:

..

5 0
3 years ago
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