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garri49 [273]
4 years ago
10

Find two numbers x and y such that their sum is 60 and x2y is maximized.

Mathematics
1 answer:
Elina [12.6K]4 years ago
3 0
X + y = 60
P = x^2 y

From first  equation y = 60 - x

P = x^2(60 - x)
P = 60x^2 - x^3
Finding the derivative of P and equating to zero:-
P' = 120x - 3x^2 = 0
 -3x ( x - 40) = 0
 x = 40 
This makes y = 20
So maximum values of x^2y  = 40^2 * 20 =  32,000.
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Find the constant of variation for the relationship f(x)= 40x
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7 0
3 years ago
Its due tonight pls hurry:///
iren [92.7K]

Answer:

a.

f(4) = 10•4 -6

f(4) = 40 -6

f(4) = 34

b.

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7 0
3 years ago
I Need Help On This
disa [49]

Answer:

The first blank: not equal

The 2nd blank: not right triangle (it's acute triangle)

The 3rd blank: equal

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Step-by-step explanation:

4^2 = 3^2 + 3^2

<=> 16 = 9 + 9

<=> 16 = 18 ( nonsense)

so triangle LKJ is not right triangle

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<=> 25 = 25 ( make sense)

so triangle ABC is right triangle

Done!! :))

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