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mel-nik [20]
3 years ago
8

What's the rule about adding intergers?​

Mathematics
1 answer:
vivado [14]3 years ago
5 0

Answer:

Integers include both positive and negative numbers, and there are several rules for adding integers. Adding two positive integers together will always result in a positive integer. For example, 6 + 4 = 10. To add two negative integers, add the numbers together and place a negative sign in front of the answer.

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What is the inverse of the function f(x) = 2x – 10
BartSMP [9]

Answer:

y = 1/2x +5

Step-by-step explanation:

change f(x) to y

y = 2x - 10

then switch x and y

x = 2y - 10

then solve for y

add 10 to both sides and divide both sides by 2

6 0
3 years ago
Read 2 more answers
If f(x)= x2 + 5, and g(x) = 3x - 11, find (g(f(-3)).
fgiga [73]

Answer:

31

Step-by-step explanation:

first find f(-3)

f(-3) = (-3)^2 +5

       = 9+5 = 14

The find g(f(-3) = g(14)

                         = 3*14-11

                           = 42-11

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6 0
3 years ago
PLZ help me and anyone who can help me will get 15 points
Liula [17]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Find the area of the shaded region
Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm

where h is the length of the altitude originating from vertex O, and so

\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm

where b is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

7 0
1 year ago
Study the box plot shown. Then enter numbers for each of the values below
Luda [366]
Answer:

Median: 16

Q1: 15

Q3: 18

Minimum: 12

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8 0
3 years ago
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