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3 years ago

9

find all numbers whose absolute value is 7. if there is more than one, separate them with commas. If there are no such numbers,

click on "none".

1 answer:

lozanna [386]3 years ago

5 0

the absolute value of 7 is 7 and the absolute value of -7 is 7

7, -7

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3 years ago

3 people can build a shed in 8 hours how long would it take 5 people

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3 years ago

Adam is using an ATM to make a withdrawal. The ATM is affiliated with a different bank than the bank where Adam has his checking

alexira [117]

Adam will most likely have to pay for ATM usage fees.

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<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>

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3 years ago

Read 2 more answers

PLEASE ANSWER ASAP I WILL GIVE BRAINLIEST Compare the slopes of the linear functions f(x) and g(x) and choose the answer that be

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7 0

3 years ago

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

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3 years ago