Answer is B, the graph increases by about 0.28 per year
Answer:
$1.27
Step-by-step explanation:
You simply just need to subtract 10.00-8.73 to get your answer which is 1.27.
Answer:
The probability that the dogs are blue eyed and deaf is 13.02%.
Step-by-step explanation:
We are given the following information in the question:
P(Blue eyes) = 31%
P(Deaf) = 38%
P(Deaf | Blue eyes) = 42%
Formula for conditional probability:

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.
Answer:
True
Step-by-step explanation:
**plug it in using the Pythagorean Theorem**
6^2+8^2= 10^2
36+64=100
100=100 (true)