Answer:
See Explanation
Explanation:
Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.
2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4
2^1 = 2^1
The rate of reaction is first order with respect to Hbn
Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.
1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4
3^1 = 3^1
The reaction is also first order with respect to CO
b) The overall order of reaction is 1 + 1=2
c) The rate equation is;
Rate = k [CO] [Hbn]
d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]
k = 3.12 * 10^-4 /[5 * 10^-4] [1.34 * 10^-3]
k = 3.12 * 10^-4/6.7 * 10^-7
k = 4.7 * 10^2 mmol-1 L s-1
e) The reaction occurs in one step because;
1) The rate law agrees with the experimental data.
2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.
Rise over run. Just like you have set up. If you plotted the data points subtract (y2-y1)/(x2-X1)
Substance A is Chlorophyll and substance B is Oxygen
Answer:
wavelength λ = 35.92 pm
Explanation:
Given that:
The glancing angle (θ) = 10.42°
Bragg reflection n = 1
wavelength λ = ???
diameter d = 99.3 pm
Using the formula:
nλ = 2dsinθ
we have:
1 × λ = 2 × ( 99.3) × sin (10.42°)
λ = 198.6 × 0.18086
λ = 35.92 pm
Explanation:
Both water and carbon dioxide have 2 bonding domains (with the 2 hydrogen atoms and 2 oxygen atoms respectively)
However, water is a polar molecule as the central oxygen atom has 2 pairs of lone electrons, which allows it to form hydrogen bonding with other water molecules.
Carbon dioxide on the other hand is non-polar because it has no lone pairs on the central carbon atom, allowing its molecular geometry to be linear.
Hence the answer is Option C.
