3 years ago

I have no Idea what this is can someone help me?

Chemistry

1 answer:

likoan [24]3 years ago

5 0

The last, because equilibrium is equal so it would have to be at an equal rate.

You might be interested in

_____ NaPO4+_____KOH

Artist 52 [7]

NaPO4 + KOH -> KPO4 + NaOH
already balance

6 0

3 years ago

Where photosynthesis takes place?

Vlad [161]

Answer:

chloroplasts

Explanation:

3 0

4 years ago

Stoichiometric coefficients indicate the ratio between ________of given substances in a chemical reaction

Cloud [144]

Answer:

Explanation:

7 0

3 years ago

A local water quality standard for a particular metal is 100 ppm. Which of the following describes what 100 ppm means?

Alborosie

Do this has extra pictures/examples so I can help?

6 0

4 years ago

How many atoms are in 73.9g of potassium oxide

denis-greek [22]

Answer: $4.69(10)^{23} atoms$

Explanation:

Firstly, we have to find the Molecular mass of potassium oxide ( $K_{2}0$ ):

$K$ atomic mass: 39 u

$O$ atomic mass: 16 u

$K_{2}O$ molecular mass: $39(2) g/mol+16g/mol=94 g/mol$

This means that in 1 mole of $K_{2}O$ there are $94 g$ and we need to find how many moles there are in $73.9 g$ $K_{2}O$ :

1 mole of $K_{2}O$ ----- $94 g$ of $K_{2}O$

$X$ ----- $73.9 g$ of $K_{2}O$

$X=\frac{(73.9 g)(1 mole)}{94 g}$

$X=0.78 mole$ This is the quantity of moles in 73.9 g of potassium oxide

Now we can calculate the number of atoms in 73.9 g of potassium oxide by the following relation:

$N_{atoms}=(X)(N_{A})$

Where:

$N_{atoms}$ is the number of atoms in 73.9g of potassium oxide

$N_{A}=6.0221(10)^{23}/mol$ is the Avogadro's number, which is determined by the number of particles (or atoms) in a mole.

Then:

$N_{atoms}=(0.78 mole)(6.0221(10)^{23}/mol)$

$N_{atoms}=4.69(10)^{23} atoms$ This is the quantity of atoms in 73.9g of potassium oxide

6 0

4 years ago