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azamat
3 years ago
7

If 42.68 ml of 0.43 M KOH is used to neutralize 18.40 ml of H, SO4, calculate

Chemistry
1 answer:
Temka [501]3 years ago
8 0

The concentration of the sulfuric acid : 0.499 M

The net ionic equation

2 OH ⁻(aq]+ 2 H ⁺ (aq] → 2 H ₂O (l]

<h3>Further explanation</h3>

Given

42.68 ml of 0.43 M KOH

18.40 ml of H2SO4

Required

the concentration of the sulfuric acid

the net ionic equation

Solution

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  

Input the value :

a=KOH, b= H2SO4

0.43 x 42.68 x 1 = Mb x 18.40 x 2

Mb = 0.499 M

The net ionic equation

Reaction

2KOH + H2SO4 → K2SO4 + 2H2O

2 K ⁺ (aq]+ 2 OH ⁻ (aq] + 2 H ⁺ (aq] + SO ₄²⁻(aq] → 2 K ⁺ (aq] + SO ₄²⁻(aq] + 2 H ₂ O (l]

canceled the spectator ions :

2 OH ⁻(aq]+ 2 H ⁺ (aq] → 2 H ₂O (l]

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The air pressure for a certain tire is 113 KPa. What is the pressure I’m atmosphere
Fynjy0 [20]

Answer: 1.11 atm

Explanation:

The unit of pressure include kilopascal (kPa), atmospheres (atm), mmHg etc

Now, given that:

Air pressure = 113 KPa

Convert kPa to atm

If 101.325 kPa = 1 atm

113 kPa = Z atm

To get the value of Z, cross multiply

Z atm x 101.325 kPa = 1 atm x 113 kPa

Z = ( 1 atm x 113 kPa) / 101.325 kPa

Z = 1.11 atm

Thus, the pressure is 1.11 atm

7 0
3 years ago
The reaction of C4H8 and Br2 to yield C4H2Br2 represents​
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Explanation:

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4 years ago
Ammonia gas occupies a volume of 2,725ml at a pressure of 701 kPa. What volume would it occupy at 101 kPa?
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3 years ago
What is the mass of one mole of Ca(OH)2?
marshall27 [118]

Answer:

74.10g/mol

Explanation:

The mass of one mole of Ca(OH)₂ is the molar mass of the compound.

To solve this problem, we add the atomic masses of the species in the compound;

 Atomic mass of Ca = 40.078g/mol

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So;

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3 0
3 years ago
Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu
masya89 [10]

Answer : The number placed in front of CuSO_4 should be, three (3).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.

In order to balanced the chemical reaction, the coefficient 3 is put before the CuSO_4, the coefficient 2 is put before the AlCl_3 and the coefficient 3 is put before the CaCl_2.

Thus, the balanced chemical reaction will be,

3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3

Therefore, the number placed in front of CuSO_4 should be, three (3).

5 0
4 years ago
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