Answer:
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Step-by-step explanation:
The constraints on protein, minerals, and vitamins give rise to the inequalities ...
   40c +30k ≥ 150 . . . . . . required protein
   20c +20k ≥ 90 . . . . . . required minerals
   10c +30k ≥ 60 . . . . . . . required vitamins
And we want to minimize 10c +12k.
The graph shows the vertices of the feasible region in (c, k) coordinates. The one that minimizes cost is (c, k) = (3.75, 0.75).
To minimize cost, the daily feed should be ...
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Daily cost will be $46.50.
 
        
             
        
        
        
Let's break apart 42.
The 4 is in the tens. The 2 is in the ones.
                            Place Value starting from Thousands
                             Thousands  Hundreds  Tens  Ones
                             _________ ________ ____ _____
                                                                        4          2
So this is how we break up numbers using place value.
Hope this helps!
 
        
             
        
        
        
Answer:
4/3 (4•5)} = 203
Step-by-step explanation:
 
        
                    
             
        
        
        
The radius is 9
The equation is
(x-h)^2 + (y-k)^2 = r^2
        
             
        
        
        
Answer:
5abc^2/35a^3c^3
Step-by-step explanation:
To bring the fraction: b/7a^2c to a denominator of 35a^3c^3, find the dividend when the 35a^3c^3 is divided by 7a^2c
=35a^3c^3/ 7a^2c
Recall that 
a^x/a^y = a^x-y
Hence
35a^3c^3/ 7a^2c = 5a^3-2c^3-1
= 5ac^2
Now multiply the numerator and denominator by the result
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2)
Recall that 
 a^x * a^y = a^x+y
Hence
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2) = 5abc^2/35a^3c^3