Answer:
letter b by replicating experiments
Explanation:
Answer:
0.090 J/(mmol·°C) × (1000 mmol/mole × 1 kJ/(1000 J)) = 0.090 kJ/mole
Explanation:
The unit of conversion from kilo-Joules to Joules is given as follows;
1000 Joules = 1 kilo-Joule
The unit of conversion from milimoles to moles is given as follows;
1000 milimoles = 1 Mole
Therefore, we have
The value of the given expression is 0.090 J/(mmol·°C) × 1000 mmol/mole × 1 kJ/(1000 J) = 0.090 kJ/mole
0.090 J/milimole = 0.09 kJ/mole.
Answer:
Explanation:
1. the 1/2 reaction that occurs at the cathode
3Cl2(g) +6e^- -------------> 6Cl^- (aq)
2 the 1/2 reaction that occurs at the anode
2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-
2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-
E0 = -0.59v
3Cl2(g) +6e^- -------------> 6Cl^- (aq)
E0 = 1.39v
3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)---------> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)
E0cell = 0.80v
There is 103 percent of water in hydrate
2.43*1000.
There are 1000 grams in a kilogram
