Answer:
![[NH_2NO_2]=0.0868M](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.0868M)
Explanation:
Hello,
In this case, for the given chemical reaction, the first-order rate law is:
![r=\frac{d[NH_2NO_2]}{dt} =-k[NH_2NO_2]](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%5BNH_2NO_2%5D%7D%7Bdt%7D%20%3D-k%5BNH_2NO_2%5D)
Which integrated is:
![[NH_2NO_2]=[NH_2NO_2]_0exp(-kt)](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D%5BNH_2NO_2%5D_0exp%28-kt%29)
Thus, the concentration after 31642.0 s for a 0.384-M solution is:
![[NH_2NO_2]=0.384M*exp(-4.70x10^{-5}s^{-1}*31642.0s)\\](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.384M%2Aexp%28-4.70x10%5E%7B-5%7Ds%5E%7B-1%7D%2A31642.0s%29%5C%5C)
![[NH_2NO_2]=0.0868M](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.0868M)
Best regards.
From the coefficients of the equation, we see that for every 4 moles of aluminum consumed, 3 moles of oxygen are consumed.
So, the answer is (12/4)(3) = 9 moles.
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➷ It would depend on whether they would create an endothermic reaction or exothermic. For a hot pack, the chemicals would need to release energy (heat). However, a cold pack would need chemicals that need to draw heat from the surroundings to produce a cool sensation.
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6 protons, 6 electrons and 13 neutrons