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3 years ago

Determine a massa de um átomo de carbono12 em gramas

Chemistry

2 answers:

Anon25 [30]3 years ago

7 0

The mass of an atom of carbon-12 is 1.993 × 10⁻²³ g.

1 C atom has a mass of 12 u.

1 mol of C atoms has a mass of 12 g.

∴ Mass of 1 C atom = 12 g/6.022 × 10²³ C atoms = 1.993 × 10⁻²³ g

lapo4ka [179]3 years ago

3 0

I believe it would be 1.660539040 × 10−24 gram.

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3 years ago

Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press

asambeis [7]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.229 atm. What is the likely formula of the compound?

A. XeO

B. $XeO_4$

C. $Xe_2O_2$

D. $Xe_2O_3$

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Answer: The chemical formula of the compound is $XeO_4$

Explanation:

To calculate the molecular mass of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{w}{M}RT$

where,

P = Pressure of the gas = 0.229 atm

V = Volume of the gas = 50.0 mL = 0.050 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = $0^oC=273K$

Putting value in above equation, we get:

$0.229\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.229\times 0.050}=195.4g/mol\approx 195g/mol$

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Hence, the chemical formula of the compound is $XeO_4$

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Please kindly check attachment for the step by step solution of the given problem.